if vectorA+vectorB=vectorC, then the angle between vectorA and vectorB is
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Parallelogram law of forces/vectors :
C^2 = A^2 + B^2 + 2 A B Cos Ф, where A, B, C are magnitudes of vectors. and Ф is the angle between A and B vectors.
Ф = Cos⁻¹ { (C² - A² - B²) / (2 A B) }
the angle is between 0 and Pi.
C^2 = A^2 + B^2 + 2 A B Cos Ф, where A, B, C are magnitudes of vectors. and Ф is the angle between A and B vectors.
Ф = Cos⁻¹ { (C² - A² - B²) / (2 A B) }
the angle is between 0 and Pi.
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A⃗ + B⃗ = C⃗
∵ A² + B² + 2ABcosθ = C²
∴ θ = cos⁻¹ [(C² - A² - B²)/2AB]
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