Question

If |vectorA×vectorBI=|A.BI. Then what will be the angle between A and B .
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Answer 1

Answer:the angle is 45

Explanation:

Look at the pin below

Answer 2

Hey mate ,

here the formulas of angle between two vectors are ,

$sin\alpha = \frac{ |A \times B| }{ |A| |B| } \: \: \: \: \: \: \: and \: \: \: \: \: \: \: cos \alpha = \frac{ |A \: \: B| }{ |A| |B|} \\ \\ here \: |A \times B| \: = |A \: \: B| \\ \\ so \\ \\ sin\alpha = \frac{ |A \: \: B| }{ |A| |B| } \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: ............(1) \\ \\ now \: from \: formulas \: and \: equation \: (1) \\ \\ sin \alpha = cos \alpha \\ \\ the \: minimum \: value \: of \: angel \: when \\ \: sin \alpha = cos \alpha \: \: \: \: \: \: \: \: \: \: is \: \frac{1}{ \sqrt{2} } \\ \\ and \: angle \: value \: is \: \frac{\pi}{4} \:$

□ so the angle is 45°

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