If vectors :A =6i and B =3j
,what is the angle between them?
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Explanation:Here we take out the magnitude of the vector A and vector B.
A = √6^2
= 6
B =√3^2
= 3
Now we can use dot product of vectors
A= 6i + 0j
B= 0i + 3j
A.B= 0
A.B= A.B cosФ
0 = 6.3 cosФ
0 = cos Ф
Ф = 90
∴ the angle between the two vectors is 90
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