If vectors A and B are such that A + B] = A= B,
then [A - B] may be equated to
(1)√3\2 [A]
(2) [A]
(3) √2A
(4) √3A
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√3\2[A]
The larger diagonal is representing the sum of vectors a and b.
The smaller diagonal is representing the difference of vectors a and b.
Using cos Rule in trigonometry,
We have |a+b|=sqrt(a*a +b*b+2*a*b*cos C)
where a and b are the two vectors and C is the angle between the two vectors a and b
and |a - b| =sqrt(a*a +b*b-2*a*b*cos C)
When |a+b|=|a - b|
Squaring both sides
(|a+b|)(|a+b|)=(|a-b|)(|a-b|)
We are left with
a*a+b*b+2*a*b*cosC =a*a+b+b-2*a*b*cosC
Cancelling and rearranging, we obtain
4*a*b*cosC = 0
cosC=0
We know that cos90 = 0
C = 90
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