if vectors A.B = /A×B/ then what is the angle between vector A and B
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Explanation:
The magnitude of a vector V is the square root of the dot product with itself, i.e. Thus, A*B = 0, making the angle between them 90 degrees.
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We know that,
A.B = AB cos(∅) ........(dot prod.)
and, A×B = AB sin(∅) ...….(cross prod)
*where ∅ is angle b/w A and B*
Now, It is given that:
A.B = A×B
=> AB cos(∅) = AB sin(∅)
=> cos(∅) = sin(∅)
=> tan(∅) = 1 = tan(π/4)
=> ∅ = π/4
Hence, the angle b/w vector A & B is π/4.
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