Physics, asked by rraj7174130, 1 month ago

If vectors A→,B→,C→,D→,E→,F→ forms the sides of a closed polygon, then vector F→ is equal to

Answers

Answered by pranjal4466
0

Explanation:

Correct option is

Correct option isD 3

Here,we will use triangle vector property

Here,we will use triangle vector propertyConsider △ACD:

Here,we will use triangle vector propertyConsider △ACD: We get

AC + CD = AD −(i)

AC + CD = AD −(i) In △ADE:

We get

AE + ED = AD −(ii).

AE + ED = AD −(ii).

AE + ED = AD −(ii). Now adding (i)&(ii)

⟹ AC + CD + AE + ED =2 AD −(iii)

⟹ AC + CD + AE + ED =2 AD −(iii)∵

⟹ AC + CD + AE + ED =2 AD −(iii)∵It is a regular hexagon,$$

⟹ AC + CD + AE + ED =2 AD −(iii)∵It is a regular hexagon,$$∴

⟹ AC + CD + AE + ED =2 AD −(iii)∵It is a regular hexagon,$$∴ AF = CD

⟹ AC + CD + AE + ED =2 AD −(iii)∵It is a regular hexagon,$$∴ AF = CD (∴Equal and parallel opposite sides)$$

⟹ AC + CD + AE + ED =2 AD −(iii)∵It is a regular hexagon,$$∴ AF = CD (∴Equal and parallel opposite sides)$$Similarily,

⟹ AC + CD + AE + ED =2 AD −(iii)∵It is a regular hexagon,$$∴ AF = CD (∴Equal and parallel opposite sides)$$Similarily, ED = AB

⟹ AC + CD + AE + ED =2 AD −(iii)∵It is a regular hexagon,$$∴ AF = CD (∴Equal and parallel opposite sides)$$Similarily, ED = AB

⟹ AC + CD + AE + ED =2 AD −(iii)∵It is a regular hexagon,$$∴ AF = CD (∴Equal and parallel opposite sides)$$Similarily, ED = AB Putting in (iii):

⟹ AC + CD + AE + ED =2 AD −(iii)∵It is a regular hexagon,$$∴ AF = CD (∴Equal and parallel opposite sides)$$Similarily, ED = AB Putting in (iii):⟹ AC + AF + AE + AB =2 AD

Adding AD on both sides

⟹ AC + AB + AD + AE + AF =3 AD

⟹λ=3

Answered by AA2008
0

Answer:

-(A+b+c+d+e+f) all are in the vector form

Explanation:

Similar questions