Physics, asked by rushikesh1452002, 1 year ago

If vectors
A=i-3j+k is parallel to B = 3i+yj+zk. The values of y and z respectively are
a) -3,1
b) -6,2
c) 9,3
d) -9,3​

Answers

Answered by chaitanyaraj
2

Answer:

Hey mate

the answer will be a) because there should must be the coordinates of two axes for parallel.

Answered by Tulsi4890
0

The values of y and z respectively are -9 and 3 (d).

Given:

A= i-3j+k and B= 3i+yj+zk are parallel to each other.

To Find:

The values of y and z.

Solution:

Vector A and vector B are parallel to each other which implies,

A=kB

Therefore, 1= 3k --- (i)

-3=yk ----(ii)

1=kz -----(iii)

From eq (i) k= 1/3

From eq (ii) and eq (iii),

y= -9

z= 3

Hence, the values of y and z respectively are -9 and 3.

#SPJ3

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