Physics, asked by kshitij4061, 1 year ago

If velocity=5cos[4t+π] calculate acceleration

Answers

Answered by Anonymous
0

its -5 sin [4t+π]×4

= - 20sin [4t+π]

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just differentiation......simple

Answered by skh2
0

we have :-

Velocity=5cos(4t+\pi)

\rule{200}{2}

We already know that :-

ACCELERATION=\dfrac{dv}{dt}

where:-

v is the velocity of the moving object

\rule{200}{2}

Applying the derivative :-

Acceleration=\dfrac{dv}{dt}\\ \\ \\a=\dfrac{d}{dt}5cos(4t+\pi)\\ \\ \\a=5\dfrac{d}{dt}cos(4t+\pi)\\ \\ \\a= 5(-sin(4t+\pi))*\dfrac{d}{dt}(4t+\pi)\\ \\ \\a=5(-sin(4t+\pi)*(4+0)\\ \\ \\a=20(-sin(4t+\pi)\\ \\ \\a=-20sin(4t+\pi)

\rule{200}{2}

Rules of Differentiation :-

y=cosx\\ \\ \\ \dfrac{dy}{dx}=(-sinx) \\ \\ \\ \\ \\y=nx\\ \\ \dfrac{dy}{dx}=n\dfrac{dx}{dx}

\rule{200}{2}

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