Question

If velocity gradient is dv/dx then, determine the velocity gradient for a particle moving along x-axis with a velocity of v = 3x + 4x2-3x +2 at a distance of 2 min positive x- direction
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Answer 1

Explanation:

v=x

2

+x

⇒

dx

dv

=2x+1

∴a=

dx

vdv

=(x

2

+x)(2x+1)

∴atr=2

a=(4+2)(4+1)

=30m/s

2