If velocity gradient is dv/dx then, determine the velocity gradient for a particle moving along x-axis with a velocity of v = 3x + 4x2-3x +2 at a distance of 2 min positive x- direction
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Explanation:
v=x
2
+x
⇒
dx
dv
=2x+1
∴a=
dx
vdv
=(x
2
+x)(2x+1)
∴atr=2
a=(4+2)(4+1)
=30m/s
2
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