Question

If velocity of a body increases 3 times, then what is the increase in k.E?

Answer 1

K.E=

$\frac{1}{2} mv {2}^{?}$

velocity is 3v

ke=

$\frac{1}{2} m \times 3v {}^{2}$

therefore

$\frac{1}{2} 3mv {2}$