Question

if velocity of a body is given by v=alphat^3/2 then dimenaion of alpha should be​

Answer 1

Correct option is

correct answer is

[ML3T−4]

The given equation is   F=βv2α−t2

The given equation is   F=βv2α−t2Dimension of α is same as that of square of time i.e.  α=[T2]

The given equation is   F=βv2α−t2Dimension of α is same as that of square of time i.e.  α=[T2]Dimensoin of β is   β=Fv2α−t2=[MLT−2][L2T−2][T2]=[M−1L−3T6]

The given equation is   F=βv2α−t2Dimension of α is same as that of square of time i.e.  α=[T2]Dimensoin of β is   β=Fv2α−t2=[MLT−2][L2T−2][T2]=[M−1L−3T6]Thus   βα=[M−1L−3T6][T2]=[ML3T−4]