if velocity of a body is half the maximum velocity. Then what is its distance from the mean position?
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Hello mate.
Thanks for asking this question.
Your answer is =>
The velocity when considered as maximum , the distance covered by that body in time t will be given as =>
Distance = Velocity × time = v× t
D = v × t ____________(1)
now, considering the velocity half the maximum velocity ,
new velocity = V / 2
so, the distance covered by that body in the same time period will be =>
distance = new velocity × t
new distance = ( V/2 ) × t______(2)
Dividing equation (2) by (1) ,
new distance / distance = ([V/2]×t) ÷ ( v×t)
new distance => Distance/2
new distance will be half of the old distance.
Thanks for asking this question.
Your answer is =>
The velocity when considered as maximum , the distance covered by that body in time t will be given as =>
Distance = Velocity × time = v× t
D = v × t ____________(1)
now, considering the velocity half the maximum velocity ,
new velocity = V / 2
so, the distance covered by that body in the same time period will be =>
distance = new velocity × t
new distance = ( V/2 ) × t______(2)
Dividing equation (2) by (1) ,
new distance / distance = ([V/2]×t) ÷ ( v×t)
new distance => Distance/2
new distance will be half of the old distance.
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