Question

If velocity of a particle is v=v(1-e-"), where and b are constants. Then,
the acceleration of the particle is b at 1=0
the maximum velocity is »
the maximum velocity is ev,
the minimum velocity is​

Answer 1

Answer:

For first lens

Image distance v = 2u = 2 × (-50) = -100 cm

For second lens

Now u = - 190 cm, f = - 8 cm, m2 = ?

Net magnification = m1 m2 = 0.08

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