Physics, asked by shubhanshi7866, 2 months ago

If velocity of an object is (2į) m/s and moves with constant
acceleration (i-)m/s2, then the velocity of the particle at the
end of 2 s is

Answers

Answered by shilamore12345
1

Explanation:

ANSWER

initial velocity u=2m/s

acceleration a = 2m/s at 60

component of acceleration in direction of velocity and perpendicular to initiail velocity according to figure

a

x

=acos60

0

=2×

2

1

=1

a

y

=asin60

0

=2×

2

3

=

3

s

x

=ut+

2

1

a

x

t

2

=2×2+

2

1

×1(2)

2

=6m

s

y

=ut+

2

1

a

x

t

2

=0+

2

1

×

3

(2)

2

=2

3

m

net displacement = S=

s

x

2

+s

y

2

=

36+12

=4

3

m

again for velocity in X any Y direction

v

x

=u+a

x

t=2+1×2=4m/s

v

y

=u+a

y

t=0+

3

×2=2

3

m/s

net velocity = V=

v

x

2

+v

y

2

=

16+12

=2

7

m/s

thus .

option A is correct

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