Question

If velocity of an object is v=t^2-2t+3, then find displacement in first 2 seconds.​

Answer 1

Answer:

displacement in first 2sec is 14/3 unit

Explanation:

Given :-velociy of an object = t²-2t + 3

time = 2sec

find:- displacement in first 2sec= ?

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We know that v = displacement /time = dx/dt (in instantaneous speed)

Let displacement is x

• ∵ V = dx/dt

• ∴ (t² -2t +3) = dx/dt
• dx = (t² -2t +3)dt
• ₀∫ˣ dx = ₀∫²(t²- 2t + 3 )dt

• [x]₀ˣ= [t³/3 - t² +3t ]₀²
• x= 2³/3 - 2² + 3× 2 -0
• x = 8/3 - 4 +3×2
• x = 8/3+2

x = 14/3 unit Answer .

Displacement in first 2sec is 14/3unit

Answer 2

Answer:

x=14/3 unit

displacement in first 2sec is 14/3 unit