If velocity of particle at t = 0 is 2 m/s. Find its velocity at t = 3s.
Answers
Answer:
initial velocity u=2m/s
acceleration a = 2m/s at 60
∘
component of acceleration in direction of velocity and perpendicular to initiail velocity according to figure
a
x
=acos60
0
=2×
2
1
=1
a
y
=asin60
0
=2×
2
3
=
3
s
x
=ut+
2
1
a
x
t
2
=2×2+
2
1
×1(2)
2
=6m
s
y
=ut+
2
1
a
x
t
2
=0+
2
1
×
3
(2)
2
=2
3
m
net displacement = S=
s
x
2
+s
y
2
=
36+12
=4
3
m
again for velocity in X any Y direction
v
x
=u+a
x
t=2+1×2=4m/s
v
y
=u+a
y
t=0+
3
×2=2
3
m/s
net velocity = V=
v
x
2
+v
y
2
=
16+12
=2
7
m/s
thus .
hope, it will help you.
Answer
initial velocity u=2m/s
acceleration a = 2m/s at 60∘
component of acceleration in direction of velocity and perpendicular to initiail velocity according to figure
ax=acos600=2×21=1ay=asin600=2×23
=3
sx=ut+21axt2=2×2+21×1(2)2=6m
sy=ut+21axt2=0+21×3
(2)2=23
m
net displacement = S=sx2+sy2
=36+12
=43
m
again for velocity in X any Y direction
vx=u+axt=2+1×2=4m/svy=u+ayt=0+3
×2=23
m/s
net velocity = V=vx2+vy2
=16+12
=27
m/s