Question

If velocity of particle varies with position as v = 2x + 5.
Find acceleration at x = 2m​

Answer 1

Answer:

v=x

2

+x

⇒

dx

dv

=2x+1

∴a=

dx

vdv

=(x

2

+x)(2x+1)

∴atr=2

a=(4+2)(4+1)

=30m/s

2

Answer 2

Answer:

acceleration=18m/$s^{2}$

Explanation:You have the equation of velocity. Just differentiate it with respect to time. so, you will get equation of acceleration as

a=2v

Find v from first equation and plug it in the second