if velocity(v) of a body in time t is given by V=At cube +BT so + CT + D. then what are the dimensions of C
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Hey,
v=at+b/t+c
We know that, Two entities can only be added if their dimensions are same,
so Dimensions of [at] = Dimensions of [b/t] = Dimensions of [c] = Dimensions of [v]
=> [aT] = [v] = [LT⁻¹]=> [a] = [LT⁻²] , Dimensions of [a]
=>[bT⁻¹] = [LT⁻¹]=> [b] = [L], Dimensions of [b]
=> [c] = [LT⁻¹] , Dimensions of [c].
HOPE IT HELPS YOU:-))
v=at+b/t+c
We know that, Two entities can only be added if their dimensions are same,
so Dimensions of [at] = Dimensions of [b/t] = Dimensions of [c] = Dimensions of [v]
=> [aT] = [v] = [LT⁻¹]=> [a] = [LT⁻²] , Dimensions of [a]
=>[bT⁻¹] = [LT⁻¹]=> [b] = [L], Dimensions of [b]
=> [c] = [LT⁻¹] , Dimensions of [c].
HOPE IT HELPS YOU:-))
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