if velocity v of a perticle moving on a straight line as a function of time t is given as v= 5-t( m/s) then the distance covered by the particle in first 10s is
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Answer:
distance is 250m
Explanation:
v= 5t
dx /dt = 5t
dx = 5 t^2/2
taking integration
x = 5 × 10×10 ÷2
x = 250m
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