Physics, asked by adityaadarshjha, 1 year ago

if velocity v of particles moving in straight line is related with distance travelled s as v=2√(1+s) where v is in m/s and s in meter.Find the accelaration of the particles 2m/s^2


Shreya98: could you clarify a bit about the values provided :)

Answers

Answered by uneq95
5
So, you need to prove that the acceleration of the particles is 2 m/s².

We have got a relation between v and s. Can't you calculate acceleration with it? Don't you know that acceleration is nothing but rate of change of velocity?
You will get acceleration by simply differentiating the expression of v with respect to time.

a =dv/dt
a = 2×(d/dt) (2√(1+s))
a= 2×(1/2)×(1/√(1+s))×(d/dt)(1+s)
a= (1/√(1+s))×v
∵ds/dt =v
a= (1/√(1+s))×(2√(1+s))
a= 2 m/s²

See, its not that difficult. Just remember the basics.

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