Question

If vernier caliper possess a positive zero error of 1.2 cm and least count of 0.01 cm.If main scale reading is 3.6cm and vernier scale division coincide with the 6 div to main scale what is the correct diameter of that object...?

Answer 1

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Answer 2

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]Least count, LC=0.01cm

Here the negative zero error of callipers =5×0.01=0.05cm and it should be added to final reading. 

Main scale reading, MSR=2.4cm and VSD=6

So total reading means the diameter of sphere R=MSR+(VSD×LC)+ zero error =2.4+(6×0.01)+0.05=2.51 cm