if vertex of a parallelogram is (2,3) and the diagonals cut at (3,-2)find the opposite vertex
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Answered by
1
Answer:
hope it may help you but sorry if you don't understand than
Step-by-step explanation:
Answer:
We know that by section formula, the co-ordinates of the points which divide internally the line segment joining the points (x
1
,y
1
) and (x
2
,y
2
) in the ratio m:n is
(x,y)=(
m+n
mx
2
+nx
1
,
m+n
my
2
+ny
1
)
O is the midpoint of AC and BD
∴(2,−5)= mid point of AC
(2,−5)=(
2
x
1
+3
,
2
y
1
+2
)
2
x
1
+3
=2
⇒x
1
+3=4
∴x
1
=1
Also,
2
y
1
+2
=−5
y
1
+2=−10
y
1
=−12
∴c=(1,−12)
(2,−5)= Mid point of BD
(2,−5)=(
2
−1+x
2
,
2
0+y
2
)
⇒
2
−1+x
2
=2
⇒−1+x
2
=4
∴x
2
=5
⇒
2
0+y
2
=−5
∴y
2
=−10
∴D=(5,−10)
Answered by
1
Answer:
(4,-7)
Step-by-step explanation:
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