If voltage across a bulb rated 110 V,50 W drops by 10%of its rated value,the percentage of the
rated value by which the power would decrease is
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Answer:
19 %
Explanation:
Power is directly proportional to the square of Voltage since R const for a bulb at a given temp. Therefore when V becomes 0.9V(drops 10 percentage) P becomes square(0.9)P=.81P.. Ie: Drops by 19%..
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