Question

If voltage across a conductor is (4+_0.1) and current is (2+ 0.1) Find resistance of conductor with error limit?​

Answer 1

Answer: 2+_ 0.15  Ω

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Explanation:

Here, V= 4 V , I = 2 A

and Δ V = 0.1 V and Δ I = 0.1 A

Now,

R= V/I = 4/2 = 2  Ω

for error, Δ R /R = Δ V/ V + Δ I /I

or, Δ R = R * (Δ V/ V + Δ I /I )

          = 2 * (0.1 / 4 + 0.1 / 2)

          = 0.15  Ω

So, resistance is 2+_ 0.15  Ω