Question

if volume of a room is 12y^3+8y^2-20y, find the dimensions of room​

Answer 1

Answer:

12y^3+8y^2-20y

=4y(3y^2+2y-5)

=4y(3y^2+5y-3y-5)

=4y{y(3y+5)-1(3y+5)}

=4y(3y+5)(4y-1)

so the dimensions of the room are

4y

(3y+5)

(4y-1)