if volume of a room is 12y^3+8y^2-20y, find the dimensions of room
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Answer:
12y^3+8y^2-20y
=4y(3y^2+2y-5)
=4y(3y^2+5y-3y-5)
=4y{y(3y+5)-1(3y+5)}
=4y(3y+5)(4y-1)
so the dimensions of the room are
4y
(3y+5)
(4y-1)
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