if volume of oxygen is 11.2 decimeter cube number of moles of Oxygen will be
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Answer:
0.5 moles
Explanation:
By using PV=nRT in STP we get V=22.4ml (decimeter cube) when n =1 when the component is in gaseous state
so if volume of oxygen is 11.2 ml(dm^3) no.of moles =11.2/22.4 =0.5 moles
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