If vx = 3 meters/second and vy = 4 meters/second, what is the magnitude of the resultant velocity?
a.
7 meters/second
B.
5 meters/second
C.
1 meters/second
D.
6 meters/second
Answers
Answered by
2
it is B 5m/s
as .......
as .......
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Answered by
1
Hey dear,
◆ Answer-
v = 5 m/s
◆ Explanation-
# Given-
vx = 3 m/s
vy = 4 m/s
θ = 90°
# Solution-
By law of vector addition, magnitude of resultant velocity is given by -
v = √(v1^2 + v2^2 + 2v1v2cosθ)
v = √(vx^2 + vy^2 + 2vx.vy.cos90)
v = √(3^2 + 4^2 + 2×3×4×0)
v = √(9 + 16)
v = √25
v = 5 m/s
Therefore, magnitude of resultant velocity is 5 m/s.
Hope this helps you...
◆ Answer-
v = 5 m/s
◆ Explanation-
# Given-
vx = 3 m/s
vy = 4 m/s
θ = 90°
# Solution-
By law of vector addition, magnitude of resultant velocity is given by -
v = √(v1^2 + v2^2 + 2v1v2cosθ)
v = √(vx^2 + vy^2 + 2vx.vy.cos90)
v = √(3^2 + 4^2 + 2×3×4×0)
v = √(9 + 16)
v = √25
v = 5 m/s
Therefore, magnitude of resultant velocity is 5 m/s.
Hope this helps you...
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