Math, asked by Opevekar686, 1 year ago

If w is a complex cube root of unity, show
that
i) (2-w)(2-w2) =7
ii) (1+w-w2)° = 64
iii) (1+w)2-(1+w2) = 0
iv) (2+w+w2)3-(1-3w+w2)3 = 65
v) (3+3w+5w2)6 –(2+6w+2w2)3 = 0​

Answers

Answered by satyaveni1857
0

Answer:

iii) (1+w)2-(1+w2)=0

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