Question

If w is a complex cube-root of unity, then prove the following.
[3] (w2 +w−1)3 = −8 ii) (a + b)+(aw+bw2 )+(aw2 +bw)= 0.​

Answer 1

Step-by-step explanation:

If w is a complex cube-root of unity, then prove the following.

(w2 +w−1)3 = −8 ii)

(a + b)+(aw+bw2 )+(aw2 +bw)= 0.

[

(w2 +w−1)3 = −8 ii) (a + b)+(aw+bw2 )+(aw2 +bw)= 0.

➡➡3w {2} = 3w = 3 this is ans