Question

if w is the complex cuberoot of unity then find the value of wraise to 12​

Answer 1

$\huge\boxed{Answer}$

If ω is a complex cube root of unity, then the value of the expression 1(2-ω)(2-ω2)+2(3-ω)(3-ω2)+... +(n-1)(n-ω)(n-ω2)(n≥2) is equal to (A) n2(n+1)24-n (B) n2(n+1)24+n (C) n2(n+1)4-n (D) n(n+1)24-n.

$\huge\mathfrak\red{itz\:Jyotsana☺}$

Answer 2

Step-by-step explanation:

since w is complex cube root of unity

Thus w is cube root of 1

Therefore ,w^3= 1

So,w^12=(w^3)^4

=(1)^4........[ since w^3=1]

=1