If w is the cube root of unity,
what is the value of 1+w+w^2
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Answer:
∴w is cube root of unity
∴w
3
=1 and 1+w+w
2
=0
(1+w+w
2
)
5
+(1+w−w
2
)
5
=(0)
5
+(−w
2
−w
2
)
5
=(−2w
2
)
5
=−32w
10
=−32(w
3
)
3
.w
=−32w
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