Question

If wahaj has one and fourth part of
the ball are his hand and total
amount
ball, he has 400 it has
the ball are
divided into one
fifty in him brother
so what is the remaining ?​

Answer 1

Answer:

Let u be the initial velocity of the ball while going upwards.

The final velocity of the ball at height x is, v=0

Using the relation; v  

2

=u  

2

+2as

we have,

0=u  

2

−2gx⟹u=  

2gx

​  

 

If t is the time taken by the ball in going up through distance x,

then 0=u+(−g)t⟹t=  

g

u

​  

 

​Total time after which the ball comes into the hand is :

T=2t=  

g

2u

​  

=2  

g

2x

​  

 

​  

 

During time T,  (n−1) balls will be in air and one ball will be in hand.

TIme of stay for each ball in hand , =  

n−1

T

= n−1

2  

g

2x  = (n−1)

2

2x

Hence, the correct option is (B)

Step-by-step explanation:

Answer 2

Answer:

Let u be the initial velocity of the ball while going upwards.

The final velocity of the ball at height x is, v=0

Using the relation; v  

2

=u  

2

+2as

we have,

0=u  

2

−2gx⟹u=  

2gx

​  

 

If t is the time taken by the ball in going up through distance x,

then 0=u+(−g)t⟹t=  

g

u

​  

 

​Total time after which the ball comes into the hand is :

T=2t=  

g

2u

​  

=2  

g

2x

​  

 

​  

 

During time T,  (n−1) balls will be in air and one ball will be in hand.

TIme of stay for each ball in hand , =  

n−1

T

=  

n−1

2    

=  

(n−1)

2

g

2x

Hence, the correct option is (B)

Step-by-step explanation:

hope it helps