Math, asked by agrimdubey2987, 1 year ago

If water flow through cylindrical pipe of dia 5 mm with speed of 10 metre per minute

Answers

Answered by ZiaAzhar89
1

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Volume flown = 1/3 PI (20)^2 * 24 = 3200 Pi

Volume flown in 1 min = (Pi* 2.5/10 * 2.5/10 * 1000) = 62.5 Pi

Therefore Time taken = 3200 Pi / 62.5 Pi = 51 min. 12 sec.

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Answered by Anonymous
5
\huge\bf\mathscr\pink{Your\: Answer}

1.9625 × {10}^{-4} {m}^{3}

step-by-step explanation:

For the cylindrical pipe,

Given,

diameter = 5 mm

=> radius (r)= 5/2 mm = 2.5 × {10}^{-3} m

Now,

In 1 minute,

distance travelled by water (h) = 10 m

So, the volume of water flown in 1 min

= π {r}^{2}h

= 22/7 × {(2.5×10^-3)}^{2}× 10 {m}^{3}

= 22/7 × 6.25 × {10}^{-6} ×10 {m}^{3}

= 19.625 × {10}^{-5} {m}^{3}

= 1.9625 × {10}^{-4} {m}^{3}
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