If water is poured into an inverted hollow cone whose semi-vertical angle is 30°, its depth increases at the rate of 2 cm/s. Rate at which the volume of water increases when the depth is 6 cm is λπ cm3/sec. The value of λ is
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0
Step-by-step explanation:
Let the height of cone =h
Radius =r
θ
°
=30°
According to question,
dt
dh
=1cm/sec
tanθ=
h
r
⇒
3
1
=
h
r
⇒r=
3
h
−−−−−(1)
Now,
dt
dv
=
dt
d
(
3
1
πr
2
h)=
3
1
π
dt
d
(r
2
h)
Using (1)
dt
dv
=
3
1
π
dt
d
(
3
h
2
h)=
3
1
π⋅
3
1
dt
d
(h
3
)
dt
dv
=
9
1
π⋅3h
2
dt
dh
=
3
π
h
2
dt
dh
When h=24cm
dt
dv
=
3
π
⋅24⋅24⋅(1)=
192πcm
2
/sec
Answered by
0
Step-by-step explanation:
ans in pic hope it's a helpful
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