If water is pumped into a 36-gallon pool at an average rate of 3 gallons per hour, at what average rate, in gallons per hour, must water be pumped out of the pool so that it takes 48 hours for the pool to be filled to capacity?
Answers
Given :- if water is pumped into a 36-gallon pool at pipe R and out of the pool at pipe S. If the rate of pumping through R is 3 gallons per hour, how many gallons per hour must be pumped out at pipe S so that it takes 48 hours for the pool to be filled to capacity ?
Solution :-
from given data we have,
- Rate of pipe R = 3 gallons per hour.
- Rate of pipe S = Let x gallons per hour.
- Capacity of pool = 36 gallon.
- Total time = 48 hours .
So,
→ 3 * 48 - x * 48 = 36
→ 48(3 - x) = 36
→ 3 - x = (36/48)
→ 3 - x = (3/4)
→ x = 3 - (3/4)
→ x = (9/4) gallons per hour. (Ans.)
Hence, water must be pumped out of the pool at the rate of (9/4) gallons per hour.
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Step-by-step explanation:
if λ= 3 per hour, μ= 4 per hour and maximum capacity K = 7 in a (M/M/1) : ( K/FIFO) system, find the average number of customers in the system