Question

if wave length of uisible light is very from 4000A° to 8000A° then calculate uisibly light​

Answer 1

Speed of electromagnetic wave v=3×10 8 m/s in vacuum.

Frequency of wave ν= λv⟹ ν∝ λ1 (∵v=same)

This means higher the wavelength of light, lower is the frequency.

Thus 4000 A

light has higher frequency than 8000 A light.

Answer 2

Step-by-step explanation:

Speed of electromagnetic wave v=3×10^8

m/s in vacuum.

Frequency of wave ν= v/λ

⟹ ν∝ 1 / λ (∵v=same)

This means higher the wavelength of light, lower is the frequency.

Thus 4000 Ao

light has higher frequency than 8000 Ao

light.

ok

thank you