Question

If wavelength of a photon is 6000A°, then energy of photon will be

Answer 1

Answer:

The energy of photon is $3.13X10^{-19} J$

1. The energy of photon is given by
2. E=hf
3. or
4. E=hc/λ
5. where
6. h is Planck constant $=6.626 X 10^{-34} J.s$
7. f is the frequency of photon
8. c is speed of light $= 3X10^{8} m/s$
9. λ is the wavelength of the photon
10. E=  $\frac{6.626 X 10^{-34} J.s X 3X 10^{8} m/s}{6X10^{-7}m }=3.13X10^{-19} J$