Question

If we add 1 to the numerator and subtract 1 from
the denominator a fraction becomes 1. It also
becomes 1/2 of we add 1 to the denominator. Then
the sum of the numerator and denominator of the
fraction is
ANSWER IS 8 .PLZ GIVE SOLUTION ..SPAMS WILL BE REPORTED​

Answer 1

Answer:

3/5

Step-by-step explanation:

let fraction be x/y

x+1/y-1=2

x-y= -2. .....(1)

x/y+1=1/2

2x-y=1. ......(2)

substracting equation (1) from equation (2) we obtain: x=3

substituting this value of x in equation (1) we obtain:3-y= -2

-y=-5

y=5

hence ,the fraction is 3/5.

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Answer 2

AnswEr :

8.

$\bf{\green{\underline{\underline{\bf{GIVEN\::}}}}}$

If we add 1 to the numerator and subtract 1 from the denominator a fraction becomes 1. It also becomes 1/2 of we add 1 to the denominator.

$\bf{\green{\underline{\underline{\bf{TO\:FIND\::}}}}}$

The sum of the numerator and denominator of the fraction is.

$\bf{\green{\underline{\underline{\bf{EXPLANATION\::}}}}}$

Let the numerator be r

Let the denominator be m

$\sf{The\:fraction\:is\:=\red{\dfrac{r}{m} }}$

So,

$\bf{\large{\underline{\underline{\tt{1_{st}\:Case\::}}}}}$

$\leadsto\sf{\dfrac{r+1}{m-1} =1}\\\\\\\leadsto\sf{r+1=m-1}\\\\\\\leadsto\sf{r=m-1-1}\\\\\\\leadsto\sf{\orange{r=m-2...................(1)}}$

$\bf{\large{\underline{\underline{\tt{2_{nd}\:Case\::}}}}}$

$\leadsto\sf{\dfrac{r}{m+1} =\dfrac{1}{2} }\\\\\\\leadsto\sf{2(r)=1(m+1)}\\\\\\\leadsto\sf{2r=m+1}\\\\\\\leadsto\sf{2(m-2)=m+1\:\:\:\:\:\:\:\underbrace{\bf{From\:(1)}}}}}\\\\\\\leadsto\sf{2m-4=m+1}\\\\\\\leadsto\sf{2m-m=1+4}\\\\\\\leadsto\sf{\orange{m=5}}$

$\star$Putting the value of m in equation (1), we get;

$\leadsto\sf{r=5-2}\\\\\\\leadsto\sf{\orange{r=3}}$

$\therefore\large{\underline{\red{\sf{The\:fraction\:is\:=\:\dfrac{r}{m} =\dfrac{3}{5} }}}}$

Thus,

$\underbrace{\sf{Their\:sum\:is\:numerator+denominator=3+5=8.}}}}}}$