Question

If we add 2+2=4, but in mine case 2+2=5 , prove that 2+2=5

Answer 1

hello users ....

Given that :
2 + 2 = 4 

we have to prove that:
2 + 2 = 5


we know that:
(a - b)² = a² + b² - 2ab

solution:-
Case - 1st
if we prove 2 = 3 
then, it seems to be possible
That 2 + 2 = 5

Now,
let . 
 =>    -6  = -6  
=>    4 - 10 = 9 - 15 
=>    2² - 10 = 3² - 15 

..( Adding square of 5/2 on both side ) ..

=>     2² - 10 + (5/2)² = 3² - 15  + (5/2)² 
=>             ( 2 - 5/2)² = (3 - 5/2)²
  ..(taking square root on both side )..
=>          √( 2 - 5/2)² = √(3 - 5/2)²

=>           ( 2 - 5/2) = (3 - 5/2)
  .. (adding 5/2 on both side)..
=>   ( 2 - 5/2 + 5/2) = (3 - 5/2  + 5/2 )

=>         2 = 3

Here,
 => 2 + 2 = 2 + (3) = 5 
 => 2 + 2 = 5

Proved..

Case-2nd
we know that
2 + 2 = 4 

Here,
we have to prove 
2 + 2 = 5 
or 
 => 4 = 5 

solution:-

let,
=>         - 20   =  - 20 
=>     16 - 36  = 25 - 45 
=>      4² - 36  = 5² - 45 
..( Adding square of 9/2 on both side ) ..
=>     4² - 36 + (9/2)²  = 5² - 45 + (9/2)²
=>      (4 - 9/2)²   =  (5 - 9/2)²
..(Taking square root on both side ) ..
=>     √(4 - 9/2)²   =  √(5 - 9/2)²

=>   (4 - 9/2)   =  (5 - 9/2)
..(Adding 9/2 on both side)..
=>   (4 - 9/2 + 9/2)   =  (5 - 9/2 + 9/2)

=>      4 = 5 
Hence;
  2 + 2 = 5 
Proved.

# # Hope it helps :)