Question

If we add x to both numerator and denominator of the fractions ⅔ and 20/23 the resulting




fractions are equal x is

Answer 1

$2 + x \div 3 + x = 20 \div 23$
.cross multiple
23(x+ 2 ) =20(x+ 3)
23x + 46 = 20x + 60
23x - 20x =60- 46
3x=14
X=4.67

Answer 2

Answer:

The value of x is 7.      

Step-by-step explanation:

Given : If we add x to both numerator and denominator of the fractions $\frac{2}{3}$ and$\frac{20}{23}$ the resulting fractions are equal.

To find : The value of x?

Solution :

According to question,

$\frac{2+x}{3+x}=\frac{20+x}{23+x}$

Cross multiply,

$(2+x)\times (23+x)=(3+x)\times(20+x)$

Solve the multiplication,

$46+2x+23x+x^2=60+3x+20x+x^2$

Place like terms together,

$2x+23x-3x-20x=60-46$

$2x=14$

$x=\frac{14}{2}$

$x=7$

Therefore, The value of x is 7.