Question

If we begin with 8mL of a glucose solution
a concentration of 0.25 mol/L and
ditute it to a volume of 0.5L, what is the
concentration of the final, diluted solution,​

Answer 1

Answer: 0.004 mol/litre

Explanation:

Consider 8ml as V1

And 0.5 l as V2

Initial concentration C1/M1 = 0.25 mol/l (M=molarity)

C2/M2 = ?

As there is a derived relation .. We have our concluded formula as ;

M2 = M1×V1 / V2

Put the values n calculate it .. Hope u get it !