If we choose velocity v, acceleration a, and force F as fundamental quantities, then what will be the dimensional formula for momentum?
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The velocity v, acceleration A and force For are chosen as fundamental quantities.
To find,
The dimensional formula of angular momentum in terms of v,A,F
Solution,
According to question,
L\propto v^xA^yF^zL∝v
x
A
y
F
z
or
L= v^xA^yF^zL=v
x
A
y
F
z
Putting the dimensional formula of L, v, A and F such that :
[ML^2T^{-1}]=k[LT^{-1}]^x{LT^{-2}]^y[MLT^{-2}
On comparing both sides of the above formula as :
z = 1 ........(1)
x + y + z = 2 ......(2)
-x -2y -2z = -1 ......(3)
On solving equation (1), (2) and (3) we get :
x = 3
y = -2
and z= 1
So, the dimensional formula of angular momentum is :
[L]=[v^3A^{-2}F][L]=[v
3
A
−2
F]
Hence, this is the required solution.
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