If we construct ∆DEF in which DE = 4cm, EF = 3cm and DF = 5cm. Then find the measure of angle E
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Answer:
it follows the Pythagoras theorem so the measure of angle e is 90 degree
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3
As 3,4&5 are pythagorean triplets therefore the triangle thus formed is a right angled triangle where the longest side
i.e DF is the hypotenuse and the vertice opposite to hypotenuse is a right angle.
Therefore angle E is 90degree
i.e DF is the hypotenuse and the vertice opposite to hypotenuse is a right angle.
Therefore angle E is 90degree
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