Question

if we divide 18 into two parts such that second part is 12 more than the twice of the first part then the two parts are​

Answer 1

let

second part =x

first part=2x+12

sum of the parts =18

2x+12+x=18

3x=18-12

3x=6

x=6/3

x=2

therefore

second part=x=2

first part=2x+12=2+12=14

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