Question

if we divide 2,3,8 digit with 2 then with which number we get 1 as remainder?​

Answer 1

Answer:

2 digit numbers of the form 3 n + 2 are the numbers which will leave a remainder

of 2 when divided by 3. These numbers are the arithmetic sequence

11,14,17,⋯,98

an=a+(n−1)d⟹98=11+(n−1)3⟹98=8+3n⟹3n=90

⟹n=30

∴There are 30 two digit numbers which will give remainder 2 when

divided by 3.

2 digit numbers of the form 9 n + 2 are the numbers which will leave a remainder

of 2 when divided by 9. These numbers are the arithmetic sequence

11,20,29,⋯,92

an=a+(n−1)d⟹92=11+(n−1)9⟹92=2+9n⟹9n=90

⟹n=10

∴There are 10 two digit numbers which will give remainder 2 when

divided by 9.

Answer 2

Answer

3  is the answer

Step-by-step explanation:

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