if we double both the current and the voltage in a circuit while keeping its resistance constant, the power
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the Voltage is doubled and the resistance is kept constant then the current will automatically double. i = V/R and 2V/R = 2i
Power = (V^2)/(R) = (I^2)*(R)
Power ratio = {[(2V)^2]/(R)} / [(V^2)/(R)] = 4/1 = 4
and,
Power ratio also = {[(2i)^2]*(R)}/[(I^2)*(R)] = 4/1 = 4
Explanation:
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