Question

If we double the age of a man and subtract it from his father's age we get 15. If we double the father's age and add it to the son's age we get 105. Find their present ages.

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Answer 1

Answer :

Currently, if father's age is x and son's age is y,

then given, x+2y=70 --- (1)

2x+y=95 --- (2)

Multiplying equation (1) with 2 we get, 2x+4y=140 --- (3)

Subtracting equation (2) from (3), we get 3y=45⇒y=15

Substituting y=15 in the equation (2), we get

2x+15=95⇒x=40

Hence, the father is 40 years old and the son is 15 years old.

Answer 2

Here is your answer:-

Presently, if father's age is x and son's age is y,

then given, x+2y=70 --- (1)

2x+y=95 --- (2)

Multiplying equation (1) with 2 we get, 2x+4y=140 --- (3)

Subtracting equation (2) from (3), we get 3y=45⇒y=15

Substituting y=15 in the equation (2), we get

2x+15=95⇒x=40

Hence, the age of father is 40 years old and the son is 15 years old.

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