If we draw a line parallel to a side of the triangle. this parallel line divides the other two sides of the triangle in equal ratio. proof.
Answers
Answered by
0
Step-by-step explanation:
Given:
DE∣∣BC
To prove that:
AE
EC
=
AD
BD
Proof:
∠AED=∠ACB Corresponding angles
∠ADE=∠ABC Corresponding angles
∠EAD is common to both the triangles
⇒ΔAED∼ΔACB by AAA similarity
⇒
AE
AC
=
AD
AB
⇒
AE
AE+EC
=
AD
AD+BD
⇒
AE
EC
=
AD
BD
Hence proved
Answered by
0
Step-by-step explanation:
Basic Proportionality Theorem - A line drawn parallel to one side of a triangle and cutting the other two sides, divides the other two sides in equal proportion. The converse of Basic Proportionality Theorem - A line drawn to cut two sides of a triangle in equal proportion is parallel to the third side.
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