If we draw any line from the centre of the circle to the tangent, then find the angle between them.
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Answered by
3
Answer:
Draw a circle with center O and take a external point P. PA and PB are the tangents.
As radius of the circle is perpendicular to the tangent.
OA⊥PA
Similarly OB⊥PB
∠OBP=90
o
∠OAP=90
o
In Quadrilateral OAPB, sum of all interior angles =360
o
⇒∠OAP+∠OBP+∠BOA+∠APB=360
o
⇒90
o
+90
o
+∠BOA+∠APB=360
o
∠BOA+∠APB=180
o
It proves the angle between the two tangents drawn from an external point to a circle supplementary to the angle subtented by the line segment
Explanation:
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Answered by
2
Answer:
180
Explanation:
It proves the angle between the two tangents drawn from an external point to a circle supplementary to the angle subtented by the line segment
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