Question

if we express the energy of a photon in Kev and the wavelenght in angstroms,then the energy of a photon can b calculated from relation​

Answer 1

Answer:

Energy of photon E=

λ

hc

(joules)=

eλ

hc

(eV)

⇒E

(

eV)=

1.6×10

−19

×λ(A

o

)

6.6×10

−34

×3×10

8

=

λ(A

o

)

12375

⇒E(keV)=

λ(A

o

)

12.37

≈

λ

12.4