if we express the energy of a photon in Kev and the wavelenght in angstroms,then the energy of a photon can b calculated from relation
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Answer:
Energy of photon E=
λ
hc
(joules)=
eλ
hc
(eV)
⇒E
(
eV)=
1.6×10
−19
×λ(A
o
)
6.6×10
−34
×3×10
8
=
λ(A
o
)
12375
⇒E(keV)=
λ(A
o
)
12.37
≈
λ
12.4
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